Recall:
Resonance
We have seen that some of the Lewis dot structures we have written can be written in two or more ways.
For example:
SO2, SO3, O3, HNO3, NO3-, CO32-, etc.
None of the structures is correct by itself, but that
the correct structure is a "mixture" of all of them.
This process of "mixing" structures is called resonance.
The official name for this linear combination or mixtures is: resonance hybrid.
The individual structures which combine to make the resonance hybrid are referred to as "contributing structures."
Resonance confers extra stability on a molecule. This is because electrons don't like to be confined so the more room you give an electron to move around the more stability you gain.
The rules are:
You can't move nuclei to make a resonance form.Probably the most important molecule that is resonance stabilized is benzene, C6H6.You can only move electrons.
All of the contributing forms must be valid Lewis dot structures.
Exceptions to the Octet Rule
1. We have already seen that H, Li, and Be do not obey the octet rule because they can gain stability with the helium, 1s2 configuration.
Boron forms some compounds in which there are only six electrons around the B atom.
BF3 forms a compound with NH3 with a coordinate covalent bond using the line pair electrons on ammonia.
Examples:
SiF51-and SiF62-
PF5 and PF61-
SF4 and SF6
ClF3 and BrF5
We have mentioned that the noble gases are very unreactive and the compounds of the noble gases have only been prepared relatively recently. Some of the first compounds of the noble gases to be prepared were XeF2 and XeF4.
3. There are some molecules which have an odd number of electrons available from the valence electrons of their constituent atoms. For these molecules it is impossible for every atom to have a complete octet.
The most common examples are: NO and NO2.
NO does not dimerize. It is stable alone. NO is an example of a free radical. Free radicals have an unpaired electron. Most free radicals are unstable and will react to pair up all the electrons. NO is stable as a free radical.
We will discuss three properties of chemical bonds in this course, bond order, bond length, and bond energy.
Bond Order
Bond order is a measure of how many pairs of electrons are shared between two atoms to bond those two atoms together. Recall that a chemical bond is a sharing of electron pairs between two atoms.
For molecules without resonance the bond order is easy.
A double bond has a bond order of 2 because the two atoms share two pairs of electrons.
Likewise, in a triple bond the bond order is 3 because three pairs of electrons are shared between the two atoms bound together.
Examples:
CO2
C2H2
Each O-O pair has a single bond and then there is a second shared pair of electrons that resonates between the two pairs of atoms.
That is, the second half of the bond in the double bond is split between the two O-O pairs.
So the bond order of bonds between each pair is 1.5. The 1 comes from the single bond and the 0.5 comes from the pair involved in the resonance.
Examples:
SO3.
If we let natom pairs = the number of atom pairs of a specific type involved in the reonance, and nelectron pairs = the number of pairs of electrons involved in the resonance then the bond order is nelectron pairs/natom pairs.
Examples:
NO3-C6H6.
Bond Length
The bond length is defined as the distance between the nuclei of the two atoms involved in the bond.
There are three effects that govern bond lengths:
Bonds with higher bond orders tend to be shorter.
Bond Energy
The bond energy is the energy required to break a chemical bond. That is, it is the energy required to split the molecule into two parts at the bond in question.
Breaking chemical bonds is an endothermic process. So DH for breaking bonds is positive. (Making a bond is the reverse of breaking a bond. Making bonds is an exothermic process, with a negative DH.) Bond energies are usually given for a mole of bonds.
We will represent the bond energy (per mole) by the symbol, D (for bond Dissociation energy). Since bond dissociation energies are endothermic, all Ds are positive.
We can use bond energies to make estimates of DHs of chemical reactions.
Example:DHreaction = SDbonds broken - SDbonds formed.
The bond energies are (from the table on p 403 of our text),N2(g) + 3 H2(g) ® 2 NH3(g).
DNºN = 945 kJ/molDH-H = 436 kJ/mol
DN-H = 391 kJ/mol.